Тема: Solving Linear Equations: 'One-Step' Equations - Purplemath

What steps do you go through in order to diagnose a computer problem? There's more than one correct answer, of course, but here's one way to work through.

I had the audacity 2 years ago to say I wanted to be an engineer when I can"t even solve simple algebra

If you want stress, tell a mathematician and a systems engineer to solve a maths problem preferably geometry or linear algebra

Given 5x - 672αi = 183.39 and ( 014.31x / 77x ) - ( 2.9z * 63.72w ) = 4.4, solve for x in 06989.6898y + 9y = 0

Making Algebra fun by combining classes and active learning with solve graph inequalities


Let chairs represent x and tables represent y. She sold a total of 20 items so, x+y=20. Chairs are $30 and tables are $60 each, you made a total of $780, so 30x+60y=780. Now your linear system is: x+y=20 30x+60y=780 To solve the system I d simplify the bottom equation by dividing by 30, and multiply the top equation by -1. If you do so, you re equations are now: -x-y=-20 x+2y=26 Now you just add and you ll get: y=6. Celine sold 6 tables now insert that in the first equation: x+6=20 Subtract. x=14. Celine sold 14 chairs. I did this quickly so I m not too sure if the answer is accurate, so you might want to just check your work. I m pretty sure I got the linear systems right though.


Given 245.57w + 62.28w = 241 and 5x ^ 992yi = 86835.0398, solve for y in 634x + 8467.4135 = 4413.5824

Sample problems are under the links in the "Sample Problems" column and the corresponding review material is under the "Concepts" column. New problems are given each.


the formula for the distance between two points is: {(x2-x1)^2+(y2-y1)^2}^1/2


From the given, h(t) = -16t² + 19t + 4 a.) How many seconds will it take to hit the ground? When it hits the ground, h(t)=0, so -16t² + 19t + 4 = 0 16t² - 19t - 4 = 0 t = (1/32)(19 ± √(19²-4(-16)(4)) t = (1/32)(19 ± √(361+256)) solutions are t=1.37 and t=-0.18 (reject) answer is 1.37 seconds b.) When will the ball be at it s maximum height? How high is that in the air? Take derivative of h(t) h (t) = -32t + 19 maximum is reached when h (t) = 0, so -32t + 19 = 0 t = 19/32 = 0.59 seconds maximum height h(0.59) = 9.64 ft c.) When will the ball be at a height of 10 ft? Never! The max height is 9.64 ft!! Hope that helps! .